11x^2+10x+1=0

Solution for 11x^2+10x+1=0 equation:

11x^2+10x+1=0

a = 11; b = 10; c = +1;
Δ = b2-4ac
Δ = 102-4·11·1
Δ = 56
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{56}=\sqrt{4*14}=\sqrt{4}*\sqrt{14}=2\sqrt{14}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2\sqrt{14}}{2*11}=\frac{-10-2\sqrt{14}}{22}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2\sqrt{14}}{2*11}=\frac{-10+2\sqrt{14}}{22}
$